This scratchpad let's you see the build up to the correlationi coefficient. If there's a strong association then each pair of z-scores will be generally in the same direction (pos/neg) and the same quantity (small/medium/large). The correlation is simply the average of the z-score products.

.00

([s11]-[mean1])/[SD1]

.00

([s21]-[mean1])/[SD1]

.00

([s31]-[mean1])/[SD1]

.00

([s41]-[mean1])/[SD1]

.00

([s51]-[mean1])/[SD1]

.00

([s61]-[mean1])/[SD1]

.00

([s12]-[mean2])/[SD2]

.00

([s22]-[mean2])/[SD2]

.00

([s32]-[mean2])/[SD2]

.00

([s42]-[mean2])/[SD2]

.00

([s52]-[mean2])/[SD2]

.00

([s62]-[mean2])/[SD2]

.00

[Z11]*[Z21]

.00

[Z12]*[Z22]

.00

[Z13]*[Z23]

.00

[Z14]*[Z24]

.00

[Z15]*[Z25]

.00

[Z16]*[Z26]

m1: .00

[mean1]

s1: .00

[SD1]

m2: .00

[mean2]

s2: .00

[SD2]

SZP: .00

[SZP]

r: .00

[SZP]/5

([s11]-[mean1])/[SD1]

([s21]-[mean1])/[SD1]

([s31]-[mean1])/[SD1]

([s41]-[mean1])/[SD1]

([s51]-[mean1])/[SD1]

([s61]-[mean1])/[SD1]

([s12]-[mean2])/[SD2]

([s22]-[mean2])/[SD2]

([s32]-[mean2])/[SD2]

([s42]-[mean2])/[SD2]

([s52]-[mean2])/[SD2]

([s62]-[mean2])/[SD2]

([Z11]*[Z21])+([Z12]*[Z22])+([Z13]*[Z23])+([Z14]*[Z24])+([Z15]*[Z25])+([Z16]*[Z26])

([s12]+[s22]+[s32]+[s42]+[s52]+[s62])/6

([s11]+[s21]+[s31]+[s41]+[s51]+[s61])/6

([s11]-[mean1])**2

([s21]-[mean1])**2

([s31]-[mean1])**2

([s41]-[mean1])**2

([s51]-[mean1])**2

([s61]-[mean1])**2

[dev2s1v1]+[dev2s2v1]+[dev2s3v1]+[dev2s4v1]+[dev2s5v1]+[dev2s6v1]

[SumOfSquares1]/5

sqrt([Variance1])

([s12]-[mean2])**2

([s22]-[mean2])**2

([s32]-[mean2])**2

([s42]-[mean2])**2

([s52]-[mean2])**2

([s62]-[mean2])**2

[dev2s1v2]+[dev2s2v2]+[dev2s3v2]+[dev2s4v2]+[dev2s5v2]+[dev2s6v2]

[SumOfSquares2]/5

sqrt([Variance2])

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